0=4x^2-15x+12

Solution for 0=4x^2-15x+12 equation:

0=4x^2-15x+12

We move all terms to the left:

0-(4x^2-15x+12)=0

We add all the numbers together, and all the variables

-(4x^2-15x+12)=0

We get rid of parentheses

-4x^2+15x-12=0

a = -4; b = 15; c = -12;
Δ = b2-4ac
Δ = 152-4·(-4)·(-12)
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{33}}{2*-4}=\frac{-15-\sqrt{33}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{33}}{2*-4}=\frac{-15+\sqrt{33}}{-8}
$